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Sunday, October 18, 2015

Verilog code for 2:1 MUX using Gate level modelling

In a previous article I posted the Verilog code for 2:1 MUX using behavioral level coding. In this post I have shared the code for the same 2:1 MUX with a gate level approach.

A 2:1 MUX is simple combinational circuit which follows the following Inputs-Output relationship:

Z = ( A \cdot \overline{S}) + (B \cdot S)

Where,
Z is the output.
A and B are data inputs.
S is the select signal.

To create the circuit, I have used built in primitive logic gates in Verilog. The gates have one output and multiple inputs. The first signal is the output and the remaining ones are inputs.

2:1 MUX with Gate level modelling:

//declare the Verilog module - The inputs and output signals.
module mux2to1(
    Data_in_0,
    Data_in_1,
    sel,
    Data_out
    );

    //what are the input ports.
    input Data_in_0;
    input Data_in_1;
    input sel;
    //What are the output ports.
    output Data_out;
    //Internal variables.
    wire not_sel;
    wire temp1,temp2;
    wire Data_out_temp;

    //NOT gate - first signal(not_sel) is output and others are inputs.
    not n1(not_sel,sel);  
    //AND   gate - first signal(temp1 and temp2) is output and others are inputs.
    and and_1(temp1,Data_in_0,not_sel);
    and and_2(temp2,Data_in_1,sel);
    //OR gate - first signal(Data_out_temp) is output and others are inputs.
    or or_1(Data_out_temp,temp1,temp2);
    
    //Assign the final value to the output port.
    assign Data_out = Data_out_temp;
    
endmodule

To simulate this code you can use the same testbench code available in this post. The simulated waveform is also available here.



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